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solving systems of equations by substitution worksheet doc

This occurs when the two lines are graphed on top of each other and so they intersect at every point on the line. You may select which type of method the student should use to solve the problems. The first thing you must do when Solving Systems of Equations by Substitution is to solve one equation for either variable. )! '" Example:   Is (1, 2) a solution of the system,  y - x =1  and  2x + y = 4? 3) Once you solved one for one of the variables, plug this solution into one of the original equations and solve for the other variable. Therefore, the solution is no solution. Solve by substitution. Students will write identify the variable, write the system of equations, and solve the systems. Solve each system by substitution. 2x - 8y = 9                        2x - 8y = 9                       -2(x  - 4y = -6)                -2x  + 8y = 12 step 3:     collect like terms:                         0 = 21 Both variables cancelled out and 0 = 21 is a false statement. + > B L N ˜ ™ £ 3 =x2+ 3x− 1 Add 2xto each side. We usually try to choose the equation where the coefficient of a variable is 1 and isolate that variable. Recall the formula:    Distance = Rate x Time NOTE:   The rate of a plane: the air speed plus tail wind                                             the air speed minus the head wind Let   d =   the distance to the town and return trip. # $ % & L s t u v ú ú ú ú õ ó ó ó ó ó ó ó ó ó ó ó ó ó ó ó ó ó ó ó ó ó ó ó gd¢_¾ gd¢_¾ v w x y z { | } ¢ Ë Ì Í Î Ï Ð Ñ Ò Ó Ô Õ Ö × Ø Ù Ú Û Ü Ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ý ÷ „þ^„þ ( °Ð/ °à=!°€"°€#@$@%° °Ð°ÐÐ ‚ 6 6 6 6 6 6 6 6 6 2 À Ð à ð 0 @ P ` p €  À Ð à ð 2 ( Ø è 0 @ P ` p €  À Ð à ð 0 @ P ` p €  À Ð à ð 0 @ P ` p €  À Ð à ð 0 @ P ` p €  À Ð à ð 0 @ P ` p €  À Ð à ð 0 @ P ` p €  8 X ø V ~ _HmH nH sH tH 8 `ñÿ 8 N o r m a l _HmH sH tH 8 @ 8 H e a d i n g 1 $@&. ChalkDoc lets algebra teachers make perfectly customized Systems of Equations worksheets, activities, and assessments in 60 seconds. 01 6x - 10y = 5                6x - 10y = 5                      -3(2x - 3y = 1)             -6x + 9y = -3 step 3:     collect like terms:         -y = 2                solve:                            y = -2step 4:     substitute y = -2 into  2x - 3y = 1,  then   2x - 3(-2) = 1                                                                             2x + 6 = 1                                                                                2x = 7                                                                                 x = 7/2The solution is (7/2, -2); a unique solution. 0 =x2+ 3x− 4 Subtract 3 from each side. x− 2y= 11 9) −5x+ y= −2 −3x+ 6y= −12 10) −5x+ y= −3 3x− 8y= 24. æ æ æ æ æ ÿÿÿÿ ú ú ú ú ú Þ ø U W W W W W W , Ö ² ˆ ¶ ƒ æ ƒ Ž æ æ ˜ Ž Ž Ž Students will use a graphing calculator to solve linear systems of equations in two variables using graphing features and table features. 3)   Matthew flew his ultra light plane to a nearby town against a head wind of 15 km/h in 2 hours 20 minutes. 2)   A financial planner wants to invest $8000, some in stocks earning 15% annually and the rest in bonds earning 6% annually. Ð Solve the following equations: 2x + y = 11 7x = 14 6x + 4y = 6 3x = –15 5x + 8y = 14 4x = 24 –3x + 2y = –5 3x = 21 8x + 3y = –9 6x = –18 9x + 8y = 6 – 7x = 14 7x + 4y = 24 4x = 16 x – 5y = 21 –6x = 24 3x + 2y = –15 2x = –18 –4x – 3y = 9 5x = 15 System s of Equations – Substitution Method This occurs when the two lines are parallel and don't intersect at any point.3)  There is an infinite number of solutions. $5000 should be invested at the 15% rate and $3000 should be invested at the 6% rate. These are worksheets you can use to practice the method. • This is already done for you for this section. The return trip with a tail wind of 15 km/h took 1 hour 24 minutes. The directions are from TAKS so do all three (variables, equations and solve) no matter what is asked in the problem. Let    x = amount of $20 bills         y = amount of $50 bills Set up a system of two equations. a) intersecting lines . To use the substitution method, we use the following procedure: Systems of Equations: Substitution Solve each system by substitution. Solving Systems of Equations Algebraically There are two methods we can use to solve a system of equations using algebra (rather than graphing). 1) y= 6x− 11 −2x− 3y= −7 2) 2x− 3y= −1. NOTE:   There are three possible types of solutions to a system. 4)   Solve         2x - 8y = 9                         x  - 4y = -6 step 1:    The variable x is chosen to eliminate.step 2:    Multiply the bottom equation by -2 so the additive inverses are 2x and -2x. é ÿ H W ž Ö × ß à À Á = úöòöêâÛÔÌò½°ÌÛöú«ú«úöêâêöòöúöêö •І†tm hÝ_^ h¶ j hÝ_^ h¶ Uh¶ 5\ h¶ h¶ 5B*\phÿ h=q 5B*\phÿ htC] 5B*\phÿ h‡© >*j h‡© h‡© EHèÿUjWÌCM Systems of Equations Worksheet 6 RTF Systems of Equations Worksheet 6 PDF View Answers . Students will then learn the algebraic methods of substitution and elimination. ChalkDoc puts the kind of material you find in Kuta Software, Math Aids, Mathalicious, EngageNY, TeachersPayTeachers, and Illustrative Mathematics all in one place. Word Problems Worksheet 3 – This 6 problem algebra worksheet will help you practice solving real life systems of equations problems using the “substitution” method. Remember solve for both “x” and “y” 1) 2x + 8y = 20 2) x = 5 y = 2 2x + y = 10 3) 5x – 2y = 3 4) 2y + x = -15 y = 2x x = 3y 5) 4x + 7y = 19 6) y = 6x + 11 y = x + 9 2y – 4x = 14 7) 2x – 8y = 6 8) x = 2y – 1 y = -7 – x 3x – 2y = -3 j m  ‘ ’ Ý õíäØÎÈ Some of the worksheets for this concept are 1 review of equations, Review systems of equations, Senior high systems of equations work doc, Systems of linear equations work answers, Practice solving systems of equations 3 different, Infinite algebra 1, Solving systems of equations word problems review … Sometimes it is not possible or convenient to solve a system of equations by graphing. 3) Substitute the value found in step 2 into any one of the original equations and solve for … 2)   Substitute the chosen equation into the unused equation and solve.3)   Substitute the value found in step 2 into any one of the original equations and solve for the remaining variable.4)   The solution can be written as an ordered pair, (x, y). ÐÏࡱá > þÿ / 1 þÿÿÿ . This is a progressive series that starts simple with all equations in standard form or slope-intercept form. Worksheet 5.2. 2. If the teller gave her a total of 15 bills, how many of each type of bill did she receive? Step 1: Pick two of the equations in your system and use elimination to get rid of one of the variables. This occurs when both variables cancel out and a true statement remains. 4" ì# í# $ $ $ R$ ]$ K% Y% b% o% &'. 1)  There is only one point of intersection. Step 2 Substitute −2x+ 3 for yin Equation 1 and solve for x. These free systems of equations worksheets will help you practice solving systems of equations using the “substituton” method. substitute (1, 2) into y - x = 1:      2 - 1 = 1                                                     1 = 1          true statementsubstitute (1, 2) into 2x + y = 4:    2(1) + 2 = 4                                                         4 = 4      true statementTherefore, (1,2) is a solution to the system. Related Topics: Math Worksheets. a) graphing . Which is not a method for solving a system of equations? Notes – Systems of Linear Equations System of Equations – a set of equations with the same variables (two or more equations graphed in the same coordinate plane) Solution of the system – an ordered pair that is a solution to all equations is a solution to the equation. Systems of Equations: Substitution Method #1 (2/27) Solve the following by using the substitution method. 2) Substitute the expression into the other equation and solve for the variable. h$Å CJ h$Å 5:>*CJ$ hº3% h¢_¾ 6CJ aJ h¢_¾ 6CJ aJ h¢_¾ CJ aJ hº3% h¢_¾ CJ aJ 4 5 m ‘ ’ “ ³ Õ Ö × Ø Ù Ú ! " Minor variations such as decimals, negative numbers, like … Solve   x + y = 8           x - y = 2 Both equations are linear. The substitution method is one of the ways to solve a system of linear equations. 3) Solve    EMBED Equation.3              2x +  y = 9        The top equation will be multiplied by the LCD of 12 to yield  4x - 3y = 3. step 1:    2x + y = 9  is the chosen equation and solve for y, then y = 9 - 2x.step 2:    substitute into unused:       4x - 3(9 - 2x) = 3              solve:                                4x - 27 + 6x = 3                                                           10x - 27 = 3                                                              10x = 30                                                                 x = 3step 3:    substitute x = 3 into y = 9 - 2x  then  y = 9 - 2(3)                                                                      y =  9 - 6                                                                      y = 3 The solution is (3, 3); a unique solution. Step 3: The results from steps one and two will each be an equation in two variables. ÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿÿì¥Á q` ø¿ ç4 bjbjqPqP 8J : : ç, ÿÿ ÿÿ ÿÿ ¤ 2 V V V V $ z , 2 j ¶ ² ( Ú Ú Ú Ú Ú Ú Ú é ë ë ë ë ë ë $ h ˆ † Ú Ú Ú Ú Ú Ú Ú $ „ „ „ Ú Ú Ú é „ Ú é „ „ ÿ K Ú ¦ P¢A…YÉ V ð º é : 0 j , ª ( K K J • T Ú Ú „ Ú Ú Ú Ú Ú Ò ² Ú Ú Ú j Ú Ú Ú Ú 2 2 2 $ V 2 2 2 V 2 2 2 ÿÿÿÿ SOLVE SYSTEMS OF EQUATIONS A system of equations refers to "n" unknowns for "n" equations. Step 2: Click the blue arrow to submit. c) skew lines . Most of the problems involve money and require the use of the distributive property. These mazes take a little longer to complete than some other mazes because the problems take longer to solve. 3)   Collect like terms and solve.4)   Substitute the value found in step 4 into any one of the original equations and solve for the other variable.5)   The solution can be written as an ordered pair, (x, y). b) substitution . 2)   Solve   x - y = -4                 7x + 5y = -28 step 1:     choose x - y = -4 and solve for x;   x = y - 4.step 2:     substitute into unused:     7(y - 4) + 5y = -28               solve:                              7y - 28 + 5y = -28                                                         12y - 28 = -28                                                             12y = 0                                                               y = 0step 3:      substitute y = 0 into  x = y - 4  then   x = 0 - 4                                                                           x = -4 The solution is (-4, 0); a unique solution.

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